Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Compound Interest

Question:

Difference between compound interest and simple interest on a sum of Rs. 900 for two years is Rs. 1. Find rate of interest.

Options:

11\(\frac{1 }{9}\)

9\(\frac{1 }{11}\)

3\(\frac{1 }{3}\)

6\(\frac{2 }{3}\)

Correct Answer:

3\(\frac{1 }{3}\)

Explanation:

Difference between CI and SI for 2 years = P(\(\frac{r}{100}\))²

ATQ,

⇒ P(\(\frac{r}{100}\))² = 1

⇒ 900(\(\frac{r}{100}\))² = 1

⇒ (\(\frac{r}{100}\))² = \(\frac{1}{900}\)

⇒ \(\frac{r}{100}\) = \(\frac{1}{30}\)

⇒ Rate = \(\frac{10}{3}\)% = 3\(\frac{1 }{3}\)%