In a 2-digit number unit's digit is 5 more than the ten's digit. If 5 times the given number is 24 more than two times the number obtained by interchanging the digits of the given number, then the given number is:
Answer & explanation
Correct answer: option 3
Let us consider that ,
Unit digit = a
and tens digit is = b
unit's digit is 5 more than the ten's digit
a = 5 + b
So number is 10b + b + 5 = 11b + 5
On interchanging the digits = 50 + 11b
According to question ,
5 ( 11b + 5 ) = 2 ( 50 + 11b ) + 24
55b + 25 = 100 + 22b + 24
33b = 99
b = 3
and a = 5 + 3 = 8
So number is ----> 38