A 220 V ac supply is connected between points A and B as shown in the figure. The potential difference across the capacitor C is:

0 V 110 V 220 V $220 \sqrt{2} V$

$220 \sqrt{2} V$

During positive half cycle, p – n junction condcuts. ∴ Potential difference across C = Peak voltage of given ac voltage $= V_0 = V_{rms}\sqrt{2} = 220\sqrt{2}V$