CUET Preparation Today
The frequency of a photon whose energy is 66.3 eV would be (Given $h= 6.63 × 10^{-34} Js$) |
$66.3 × 10^{16} Hz$ $3.32 × 10^{16} Hz$ $1.6 × 10^{16} Hz$ $8.9 × 10^{16} Hz$ |
$1.6 × 10^{16} Hz$ |
The correct answer is Option (3) → $1.6 × 10^{16} Hz$ |
