Two cards are drawn without replacement. The probability distribution of number of aces is given by :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1)
| X | 0 | 1 | 2 |
| P(X) | $\frac{188}{221}$ | $\frac{32}{221}$ | $\frac{1}{221}$ |
X → no. of aces drawn
4 → no. of aces
52 → total cards
$P(X=0)=\frac{{^{48}C}_2}{{^{52}C}_2}=\frac{188}{221}$
$P(X=1)=\frac{{^{48}C}_1×{^4C}_1}{{^{52}C}_2}=\frac{32}{221}$
$P(X=2)=\frac{{^{4}C}_2}{{^{52}C}_2}=\frac{1}{221}$