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If A = 10º, what is the value of : $\frac{12sin3A+5cos(5A-5^o)}{9sin\frac{9A}{2}-4cos(5A+10^o)}$? |
$\frac{6\sqrt{2}+5}{(9-2\sqrt{2})}$ $\frac{6\sqrt{2}-5}{(9-2\sqrt{2})}$ $\frac{(9-2\sqrt{2})}{6\sqrt{2}+5}$ $\frac{6\sqrt{2}+_5}{(9+2\sqrt{2})}$ |
$\frac{6\sqrt{2}+5}{(9-2\sqrt{2})}$ |
$\frac{12sin3A+5cos(5A-5^o)}{9sin\frac{9A}{2}-4cos(5A+10^o)}$ = \(\frac{12 sin30º 5cos(50º - 5º)}{9sin45º - 4 cos 60º }\) = \(\frac{12 × 1/2 + 5/√2}{9× 1/√2 - 4 × 1/2 }\) = \(\frac{6√2 + 5}{9- 2√2 }\) |
