Two cyclists X and Y start at the same time from place A and go towards place B at a speed of 6 km/h and 8 km/h, respectively. Despite stopping for 15 minutes during the journey, Y reaches 10 minutes earlier than X. The distance between the places A and B is:

10 km

Given :-

Speed of X = 6 km/h and speed of Y = 8 km/h

Ratio of X and Y = 6 : 8

Speed                  3 : 4

Time                    4 : 3


As we know, Time is inversely proportional to speed.

The time difference = 15 min + 10 min = 25 min

4R - 3R = 25 min

1R = 25 min

Time taking by X = 4 × 25 = 100 min

= \(\frac{100}{60}\) hour

Hence ,  Distance covered by X in \(\frac{100}{60}\) hour = \(\frac{100}{60}\) × 6 = 10 km