Practicing Success
The average of four consecutive even numbers is 15. The 2nd highest number is: |
20 18 14 16 |
16 |
No's. are : 12, 14, 16, 18 in which 15 lies exactly in the middle and also the average of all four numbers. Therefore, 2nd highest no. is 16
Alternate solution: Let the first even number be 2n; Then ; required number can be written as 2n, 2n+2, 2n+4, 2n+6 Average = 15 ⇒ \(\frac{(2n)+(2n+2)+(2n+4)+(2n+6)}{4}\) ⇒ \(\frac{8n+12}{4}\) = 15 ⇒ 2n+3 = 5 2n = 12 or n = 6 2nd highest number = 2n + 4 = 16 |