Practicing Success
$\int \frac{\cos 2 x}{\cos x} d x$ is equal to |
2 sin x + log (sec x – tan x) + c 2 sin x - log (sec x – tan x) 2 sin x + log (sec x + tan x) + c 2 sin x - log (sec x + tan x) + c |
2 sin x - log (sec x + tan x) + c |
$I=\int \frac{2 \cos ^2 x-1}{\cos x} d x$ $I=\int(2 \cos x-\sec x) d x=2 \int \cos x d x-\int \sec x d x$ = 2 sin x – log| sec x + tan x| + c Hence (4) is the correct answer. |