CUET Preparation Today
The unit vector which is perpendicular to \(\hat{i}+\hat{j}+\hat{k}\) and \(\hat{i}+\hat{k}\) is |
\(\hat{i}\) \(\hat{i}-\hat{k}\) \(\frac{\hat{i}-\hat{k}}{\sqrt{2}}\) \(\frac{\hat{i}+\hat{k}}{\sqrt{2}}\) |
\(\frac{\hat{i}-\hat{k}}{\sqrt{2}}\) |
Note that \(\vec{a}\times \vec{b}\)= \(\hat{i}-\hat{k}\) $\hat p=\frac{(\hat{i}-\hat{k})}{|\hat{i}-\hat{k}|}$ and thus after normalising required vector is \(\frac{\hat{i}-\hat{k}}{\sqrt{2}}\) |
