If 0° < θ < 90°
find \(\frac{{sin}^{2}52+2+sin^238}{4sin^247+5+4cos^243}\)
Answer & explanation
Correct answer: option 2
If sum of θ = 90°
Put then equal
Put θ = 45°
⇒ \(\frac{\frac{1}{2}+2+\frac{1}{2}}{\frac{4}{2}+5+\frac{4}{2}}\)=\(\frac{3}{9}\) = \(\frac{1}{3}\)