If A $=\frac{18÷9×4}{15÷3×5}$ and B $=\frac{18÷36×3+5×1-6}{18÷6×20-3×4+12}$, then what is the value of (A + B) ?

$\frac{197}{600}$

If A $=\frac{18÷9×4}{15÷3×5}$

B $=\frac{18÷36×3+5×1-6}{18÷6×20-3×4+12}$

Then what is the value of (A + B) ?

A $=\frac{18÷9×4}{15÷3×5}$ = \(\frac{8}{25}\)

B $=\frac{18÷36×3+5×1-6}{18÷6×20-3×4+12}$ = $\frac{1÷2}{60}$

B = $\frac{1}{120}$

Put them in required equation,

(A + B) = \(\frac{8}{25}\) + $\frac{1}{120}$

(A + B) = \(\frac{192 + 5}{600}\)

(A + B) = $\frac{197}{600}$