Practicing Success
Practicing Success
CUET Preparation Today
Consider an electron in the nth orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength λ of that electron as |
(0.259) nλ $\sqrt{n}$ λ (13.6) λ nλ |
nλ |
According to Bohr's theory $m v r=n \frac{h}{2 \pi}$ $\Rightarrow$ Circumference $2 \pi r=n\left(\frac{h}{m v}\right)=n \lambda$ |
