Consider an electron in the nth orbit of a hydrogen atom in the Bohr model. The circumference of the orbit can be expressed in terms of the de Broglie wavelength λ of that electron as
Answer & explanation
Correct answer: option 4
According to Bohr's theory $m v r=n \frac{h}{2 \pi}$
$\Rightarrow$ Circumference $2 \pi r=n\left(\frac{h}{m v}\right)=n \lambda$