Consider the LPP,

Max Z = x + y, subject to the conditions

x + y ≤ 3,

x - y ≥ 1

x ≥ 0, y ≥ 0, then which of the following is not the corner point of the feasible region of above LPP.

(0, 3)

The correct answer is Option (3) → (0, 3)

$x + y ≤ 3$ or $\frac{x}{3}+\frac{y}{3}≤ 3$

$x - y ≥ 1$ or $\frac{x}{1}-\frac{y}{1}≥ 1$

$x, y ≥ 0$

intersection of eq. (1) → $x+y=3$

eq. (2) → $x-y=1$

eq. (1) + eq. (2)

$⇒x=2$

so $y=1$

so (0, 3) is not a corner point