Consider the LPP,
Max Z = x + y, subject to the conditions
x + y ≤ 3,
x - y ≥ 1
x ≥ 0, y ≥ 0, then which of the following is not the corner point of the feasible region of above LPP.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → (0, 3)
$x + y ≤ 3$ or $\frac{x}{3}+\frac{y}{3}≤ 3$
$x - y ≥ 1$ or $\frac{x}{1}-\frac{y}{1}≥ 1$
$x, y ≥ 0$
intersection of eq. (1) → $x+y=3$
eq. (2) → $x-y=1$
eq. (1) + eq. (2)
$⇒x=2$
so $y=1$
so (0, 3) is not a corner point