Practicing Success
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age? |
2 times 2 and 1/2 times 2 and 3/4 times 3 times |
2 times |
Let Ronit's age = x, then, according to the question, father's age = 3x + x 3x + x + 8 = \(\frac{5 }{2}\) (x+ 8) 4x + 8 = \(\frac{5 }{2}\)x + 20 \(\frac{3 }{2}\)x = 12 x = \(\frac{24}{3}\) = 8 As, Ronit's age = x i.e. 8 years, his father's age according to the question is 32 years. 16 years from now, Ronit's age will be: 24 years and his father's age will be 48 years, which is 2 times the age of "Ronit". Thus, the answer is 2 times.
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