Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer & explanation
Correct answer: option 1
Let Ronit's age = x, then, according to the question, father's age = 3x + x
3x + x + 8 = \(\frac{5 }{2}\) (x+ 8)
4x + 8 = \(\frac{5 }{2}\)x + 20
\(\frac{3 }{2}\)x = 12
x = \(\frac{24}{3}\) = 8
As, Ronit's age = x i.e. 8 years, his father's age according to the question is 32 years.
16 years from now, Ronit's age will be: 24 years and his father's age will be 48 years, which is 2 times the age of "Ronit".
Thus, the answer is 2 times.