In ΔABC, if ∠B = 90°, AB = 21, BC = 20 cm. Find \(\frac{1 + SinA - 2}{1 + SinA + 2}\).
Answer & explanation
Correct answer: option 1
(Triplet → 20, 21, 29)
⇒ \(\frac{1 + sinA -2}{1 + sinA + 2}\) = \(\frac{1 + \frac{21}{29} - 2}{1 + \frac{21}{29} + 2}\)
⇒ \(\frac{\frac{50 - 58}{29}}{\frac{50 + 58}{29}}\) = \(\frac{-8}{108}\) = \(\frac{-2}{27}\)