Which of the following reactions are correct?

Choose the correct answer from the options given below:

B, D, E only

The correct answer is option 2.  B, D, E only.

This reaction is not possible as \(R-NO_2\) on reduction gives \(R-NH_2\) but the reagent \(KMnO_4\) is an oxidizing agent so this is not possible.

Tin reacts with hydrochloric acid to form Tin(IV) chloride. The \(H^+\)  ions present react with the nitro group of the aromatic compound.

The oxygen from the nitro group is released in the form of water molecules. In place of oxygen atoms, hydrogen gets substituted leading to the formation of amine.

This reaction is incorrect.

Alkyl cyanides or alkyl nitriles on acid or alkaline hydrolysis give corresponding carboxylic acids. When alkyl cyanide is boiled with dilute mineral acid, it gives corresponding carboxylic acid. In this, acid amide is obtained as the intermediate product. The correct reaction shhould be as follows:

\(H_2/Pd\) is a reducing agent and reduces cyanide to primary amines. So the reaction is correct.

Amides can be reduced to amines with a strong reducing agent like lithium aluminum hydride \((LiAlH_4)\). The purpose of water at the end is for “workup”, which neutralizes strongly basic reagents at the end of the reaction.