A man rides his bicycle for 10 kilometres at a speed of 12 kilometres per hour, then for another 12 kilometres at a speed of 10 kilometres per hour. What is his average speed for the entire trip approximately?

10.8 km/h

Total distance = 12 + 10 = 22 km

Time 1 taken = \(\frac{Distance }{Time}\)

= \(\frac{10}{12}\) = \(\frac{5}{6}\)

Time 2 = \(\frac{12}{10}\) = \(\frac{6}{5}\)

Total time =  \(\frac{5}{6}\) + \(\frac{6}{5}\)

= \(\frac{25 + 36 }{30}\) = \(\frac{61}{30}\)

Average Speed = \(\frac{22 × 30}{61}\) = 10.819

= 10.8 km/h    ( approx.)