Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Communication

Question:

A 400 watt carrier is modulated to a depth of 75%. Calculate the total power in the modulated wave.

Options:

256 W

165 W

512 W

None of these.

Correct Answer:

512 W

Explanation:

Pt = Pc [ 1 + \(\frac{\mu^2}{2}\) ]

Pc = 400 W ; \(\mu\) = 75%

Pt = 512.5 kW