Practicing Success
A cube of maximum possible volume is removed from a solid wooden sphere of radius 6 cm. The side of the cube is: |
$4\sqrt{3}$cm $3\sqrt{3}$cm $6\sqrt{3}$cm $2\sqrt{3}$cm |
$4\sqrt{3}$cm |
We know that, Diagonal of cube = \(\sqrt {3}\) × Side of cube We have, Radius of the sphere = 6 cm then, Diameter of the sphere = 2 × 6 = 12 cm We also know that, Diagonal of cube = Diameter of sphere \(\sqrt {3}\) × Side of cube = 12 = Side = 4\(\sqrt {3}\) |