Practicing Success
Ve and Vp denote the escape velocities from the earth and another planet having twice the radius and the same mean density as the earth, then |
Ve = Vp Ve = Vp/2 Ve = 2Vp Ve = Vp/4 |
Ve = Vp/2 |
$\frac{\mathrm{v}_{\mathrm{e}}(\text { earth })}{\mathrm{v}_{\mathrm{p}} \text { (planet) }}=\frac{\mathrm{v}_{\mathrm{e}}}{\mathrm{v}_{\mathrm{p}}}=\frac{1}{2} ∴ \mathrm{v}_{\mathrm{e}}=\frac{\left(\mathrm{v}_{\mathrm{p}}\right)}{2}$ |