Consider the LPP: Max $Z= 5x + 3y$ subject to $3x+5y≤15,5x + 2y≤ 10,x ≥0,y≥0$
Match List-I with List-II
|
List-I |
List-II |
|
(A) Objective function |
(I) $3x+5y≥15$ |
|
(B) One constraint |
(II) $x,y≥0$ |
|
(C) Non-negative restrictions |
(III) $Z=5x+3y$ |
|
(D) Point (1, 2) does not lie in the region |
(IV) $3x+5y≤15$ |
Choose the correct answer from the options given below.
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
|
List-I |
List-II |
|
(A) Objective function |
(III) $Z=5x+3y$ |
|
(B) One constraint |
(IV) $3x+5y≤15$ |
|
(C) Non-negative restrictions |
(II) $x,y≥0$ |
|
(D) Point (1, 2) does not lie in the region |
(I) $3x+5y≥15$ |
Given LPP: $\max Z=5x+3y$ s.t. $3x+5y\le15,\;5x+2y\le10,\;x\ge0,\;y\ge0$.
(A) Objective function → $Z=5x+3y$. (III)
(B) One constraint → $3x+5y\le15$. (IV)
(C) Non-negative restrictions → $x,y\ge0$. (II)
(D) Point $(1,2)$ does not lie in the region → statement equivalent to $3x+5y\ge15$ (false for $(1,2)$), so match (I).
Final matching: (A)–(III), (B)–(IV), (C)–(II), (D)–(I)