Practicing Success
What is the correct order of increasing strength of the following ions as a reducing agent? (a) Cr2+ (b) Cr3+ (c) Cr2O72- |
Cr2+ < Cr3+ < Cr2O72- Cr2O72- < Cr3+ < Cr2+ Cr2+ < Cr2O72- < Cr3+ Cr3+ < Cr2O72- < Cr2+ |
Cr2O72- < Cr3+ < Cr2+ |
The correct answer is option 2. \(Cr_2O_7^{2-} < Cr^{3+} < Cr^{2+}\). Let us delve into the concept of reducing agents and standard reduction potentials to clarify the order of increasing strength of the given ions as reducing agents: Standard Reduction Potentials The standard reduction potential (\(E^\circ\)) of a half-reaction indicates the tendency of a species to gain electrons and be reduced. The more positive the reduction potential, the greater the species' affinity for electrons and the stronger it is as an oxidizing agent. Conversely, a species with a more negative reduction potential is more likely to donate electrons and act as a reducing agent. Given Ions and Their Reduction Potentials 1. \(\text{Cr}^{3+}\) to \(\text{Cr}\) \(\text{Cr}^{3+} + 3e^- \rightarrow \text{Cr} \quad E^\circ = -0.74 \, \text{V}\) This reduction potential indicates that \(\text{Cr}^{3+}\) is less likely to gain electrons compared to species with more positive potentials, making it a weaker reducing agent. 2. \(\text{Cr}^{2+}\) to \(\text{Cr}\) \(\text{Cr}^{2+} + 2e^- \rightarrow \text{Cr} \quad E^\circ = -0.91 \, \text{V}\) This more negative reduction potential indicates that \(\text{Cr}^{2+}\) is more likely to donate electrons compared to \(\text{Cr}^{3+}\), making it a stronger reducing agent. 3. \(Cr_2O_7^{2-}\) to \(\text{Cr}^{3+}\) \(\text{Cr}_2\text{O}_7^{2-} + 14H^+ + 6e^- \rightarrow 2\text{Cr}^{3+} + 7H_2O \quad E^\circ = +1.33 \, \text{V}\) This very positive reduction potential means that \(\text{Cr}_2\text{O}_7^{2-}\) strongly prefers to gain electrons, making it a very poor reducing agent and a strong oxidizing agent. Reducing Agent Strength A reducing agent donates electrons to another species. The strength of a reducing agent is inversely related to its reduction potential: the more negative the reduction potential, the stronger the reducing agent. Order of Reducing Strength Given the reduction potentials: \(\text{Cr}_2\text{O}_7^{2-}\) with a very positive potential is a very weak reducing agent (strong oxidizing agent) \(\text{Cr}^{3+}\) with a moderately negative potential is a moderate reducing agent. \(\text{Cr}^{2+}\) with a more negative potential is the strongest reducing agent among the three.Thus, the order of increasing strength of reducing agents (from weakest to strongest) is: So, the correct option is: \(Cr_2O_7^{2-} < Cr^{3+} < Cr^{2+}\). |