The perimeter of an equilateral triangle is equal to circumference of a circle. The ratio of their areas is:
Answer & explanation
Correct answer: option 1
Perimeter of equilateral triangle = 3a
ATQ,
⇒ 3a = circumference of circle
⇒ 3a = 2\(\pi\)r
⇒ a : r = 2\(\pi\) : 3
Area of circle = \(\pi r^2\)
Area of equilateral triangle = \(\frac{\sqrt {3}}{4} a^2\)
Required ratio = \(\frac{\sqrt {3}}{4} a^2\) : \(\pi r^2\)
= \(\frac{\sqrt {3}}{4}\) (2\(\pi\))2 : \(\pi\) 32
= \(\pi\) : 3\(\sqrt {3}\)
= 22 : 21\(\sqrt {3}\)