How much amount will be received on a principal of ₹10,000 at the rate of 12% per annum, compounded annually for 2 years?

₹12,544

From the formula for compound interest, we know,

Amount = P(1+$\frac{R}{100})^t$

 = 10000 [ 1 + \(\frac{12}{100}\) ]² - 1200

 = 10000 [ \(\frac{28}{25}\) × \(\frac{28}{25}\)  - 1 ]

 = 10000 [ \(\frac{784}{625}\)  ]

= Rs. 12544