A bus travels 50% faster than a car. Both start moving at the same time from station P and reach station Q at the same time. The stations are 100 km apart. If on the way the bus stops at the bus stop for 10 minutes, find the speed of the car.

200 Km/hr

The correct answer of the question is in the option: (1)

50% = \(\frac{1}{2}\)

Ratio of speed of Bus to car =  3 :  2

We know,

Speed = \(\frac{Distance}{Time}\)

{ Speed is inversely proportional to time )

So, ratio of time taken by Bus to car = 2 : 3

Here,

Time taken by car = 3R

Time taken by bus = 2R + stoppage time

ATQ,

3R - 2R = 10 min

1R = 10 min

Time taken by car = 3 × 10 = 30 minutes

Speed of car = \(\frac{100}{30}\) × 60 = 200 km/hr