The semi-major axis of the orbit of satellite
Answer & explanation
Correct answer: option 1
Now semi–major axis a = $\frac{-GMm}{2 E}=-\frac{6.67 \times 10^{-11} \times 5.97 \times 10^{24} \times 5000}{2 \times\left(-1.5 \times 10^{10}\right)}$
= 6.6 × 107 m