At the reduction-electrode this reaction

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Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Electro Chemistry

Question:

At the reduction-electrode this reaction takes place, A²⁺ + 2e^- ⇔ A. Which is/are correct relation for electrode potential?

Options:

E = E^o_A2+/A - $\frac{RT}{2F}$ln$\frac{[A]}{[A^{2+}]}$

E = E^o_A2+/A + $\frac{RT}{2F}$ln$\frac{[A]}{[A^{2+}]}$

E = E^o_A2+/A + $\frac{RT}{F}$ln$\frac{[A]}{[A^{2+}]}$

E = E^o_A2+/A - $\frac{RT}{F}$ln$\frac{[A]}{[A^{2+}]}$

Correct Answer:

E = E^o_A2+/A - $\frac{RT}{2F}$ln$\frac{[A]}{[A^{2+}]}$

Explanation:

The electrode potential at any concentration measured with respect to standard hydrogen electrode can be represented by:

E = E^o_M2+/M - $\frac{RT}{nF}$ln$\frac{[M]}{[M^{2+}]}$