Practicing Success
Practicing Success
CUET Preparation Today
Simplify $\frac{x^2+2 x+y^2}{x^3-5 x^2}$ if $x+\frac{y^2}{x}=5$. |
$\frac{5}{y^2}$ $\frac{7}{y^2}$ $-\frac{5}{y^2}$ $-\frac{7}{y^2}$ |
$-\frac{7}{y^2}$ |
Simplify $\frac{x^2+2 x+y^2}{x^3-5 x^2}$ If $x+\frac{y^2}{x}=5$ then x2 + y2 = 5x put in $\frac{x^2+2 x+y^2}{x^3-5 x^2}$ = $\frac{5x +2 x}{x(x^2-5 x)}$ = \(\frac{5x +2 x}{x(x^2-x^2 + y^2)}\) = \(\frac{7x}{-xy^2}\) = $-\frac{7}{y^2}$ |
