Simplify $\frac{x^2+2 x+y^2}{x^3-5 x^2}$ if $x+\frac{y^2}{x}=5$.
Answer & explanation
Correct answer: option 4
Simplify $\frac{x^2+2 x+y^2}{x^3-5 x^2}$
If $x+\frac{y^2}{x}=5$
then x2 + y2 = 5x put in $\frac{x^2+2 x+y^2}{x^3-5 x^2}$
= $\frac{5x +2 x}{x(x^2-5 x)}$
= \(\frac{5x +2 x}{x(x^2-x^2 + y^2)}\)
= \(\frac{7x}{-xy^2}\) = $-\frac{7}{y^2}$