When a ${ }_4 B e^9$ atom is bombarded with $\alpha-$ particles, one of the product of nuclear transmutation is ${ }_6 C^{12}$. The other is
Answer & explanation
Correct answer: option 4
${ }_4 \mathrm{Be}^9+{ }_2 \mathrm{He}^4 \rightarrow{ }_6 \mathrm{C}^{12}+{ }_0 n^1$