Practicing Success
Practicing Success
CUET Preparation Today
A uniform magnetic field \(\vec{B}\) is established along the positive z-direction. A rectangular loop of sides 'a' and 'b' carries a current of I as shown in figure. The torque in the loop is:
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\(IabB(-\hat{j})\) \(IabB(\hat{j})\) \(IabB(\hat{k})\) \(IabB(\hat{i})\) |
\(IabB(-\hat{j})\) |
$ \vec{\tau} = NI\vec{A}\times\vec{B} = I ab\hat{i} \times B\hat{k}$ $\Rightarrow \vec{\tau } = IabB (-\hat{j})$ |
