IUPAC name of the following compound is:

4-Bromopent-2-ene

The correct answer is Option (1) → 4-Bromopent-2-ene

1. Choose the longest chain containing C=C

2. Give double bond lowest locant

3. Then number substituents

Step 1: Identify the longest chain containing the double bond

From the structure:

$CH_3-CH=C-CH(Br)-CH_3$

That is a 5-carbon chain pent.

Step 2: Number the chain

Rule: Double bond gets the lowest possible number.

Numbering from the left:

Double bond is between C2 and C3 $\rightarrow$ pent-2-ene.

If we numbered from right, double bond would be at 3 $\rightarrow$ not preferred.

Step 3: Position of substituent

Bromine is on carbon 4.

So name = 4-Bromopent-2-ene