If $P(A) = \frac{1}{4}, P(B)=\frac{1}{2}, P(A ∪ B) =\frac{5}{8}$, then P(A ∩ B) is
Answer & explanation
Correct answer: option 2
We have,
$P(A) = \frac{1}{4}, P(B)=\frac{1}{2}$ and $P (A ∪ B) =\frac{5}{8}$.
$∴ P(A ∩ B)=P(A) +P(B)- P(A ∩ B)$
$ ⇒ P(A ∩ B)=\frac{1}{4}+\frac{1}{2}-\frac{5}{8}=\frac{1}{8}$