If $a - \frac{24}{a} = 5, $ where a > 0, then the value of $a^2 +\frac{64}{a^2}$ is :
Answer & explanation
Correct answer: option 4
If $a - \frac{24}{a} = 5, $ where a > 0,
then the value of $a^2 +\frac{64}{a^2}$
Put the value of a = 8 (This value will satisfy the given equation)
= $a^2 +\frac{64}{a^2}$ = $8^2 +\frac{64}{8^2}$
= $a^2 +\frac{64}{a^2}$ = 64 + 1 = 65