Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If $a - \frac{24}{a} = 5, $ where a > 0, then the value of $a^2 +\frac{64}{a^2}$ is :

Options:

45

56

60

65

Correct Answer:

65

Explanation:

If $a - \frac{24}{a} = 5, $ where a > 0,

then the value of $a^2 +\frac{64}{a^2}$

Put the value of a = 8 (This value will satisfy the given equation)

= $a^2 +\frac{64}{a^2}$  = $8^2 +\frac{64}{8^2}$ 

= $a^2 +\frac{64}{a^2}$  = 64 + 1 = 65