Two chords AB and CD of a circle intersect each other at P internally. If AP = 3.5 cm, PC = 5 cm, and DP = 7 cm, then what is the measure of PB?
Answer & explanation
Correct answer: option 3
As we know,
AP x PB = PC x PD
3.5 x PB = 5 x 7
PB = \(\frac{5\;×\;7}{3.5}\) = 10 cm.