Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Calculus

Question:

Two statements are given, one labelled Assertion (A) and the other labelled Reason (R).

Let $f (x) = x^4 - 2x^2 + 5$ be defined on [−2, 2].

Assertion (A): The range of $f(x)$ is [2, 13].
Reason (R): The greatest value of $f$ is attained at $x = 2$.

Select the correct answer from the options given below.

Options:

Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).

Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).

Assertion (A) is true, but Reason (R) is false.

Assertion (A) is false, but Reason (R) is true.

Correct Answer:

Assertion (A) is false, but Reason (R) is true.

Explanation:

The correct answer is Option (4) → Assertion (A) is false, but Reason (R) is true.

$f(x) = x^2 - 2x^2+5⇒ f'(x) = 4x^3 - 4x$

$⇒f'(x) = 4x (x-1) (x + 1)$

$⇒f'(x) = 4x (x^2 - 1) ⇒ f'(x) = 4x (x − 1) (x + 1)$.

For critical points, $f'(x) = 0⇒ x = 0, −1, 1$.

Now, $f(-2)=(-2)^4-2(-2)^2+5=16-8+5=13$

$f(2) = 2^4-2(2)^2+5=16-8+5=13$

$f(-1)=(-1)^4-2(-1)^2+5=1-2+5=4$

$f(0) = 0-2 × 0+5=5$

$f(1) = 1^4 - 2(1)^2 + 5 = 4$.

So, the range of $f$ is [4, 13]

∴ Assertion is false.

Also, $f$ attains it maximum value at $x = -2$ and $x = 2$

∴ Reason is true.