The rate of change of area of a circle with respect to its circumference when radius is 4cm, is |
$2\, cm^2/cm$ $4\, cm^2/cm$ $8\, cm^2/cm$ $16\, cm^2/cm$ |
$4\, cm^2/cm$ |
The correct answer is Option (2) → $4\, cm^2/cm$ $A=\pi r^2,\; C=2\pi r$ $\frac{dA}{dr}=2\pi r,\;\frac{dC}{dr}=2\pi$ $\frac{dA}{dC}=\frac{\frac{dA}{dr}}{\frac{dC}{dr}}=r$ At $r=4$ $\frac{dA}{dC}=4$ The required rate of change is $4\ \text{cm}$. |