Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Logical and Analytical Reasoning

Topic

Coding Decoding

Question:

If O = 1 and E = 17, and OPEN = 46, then PAINTER = _____.

Options:

84

85

92

89

Correct Answer:

89

Explanation:

THE LOGIC FOLLOWED HERE IS :

HERE GIVEN O = 1 AND  E = 17

THEREFORE

LET ASSUME ALPHABET IS STARTING WITH O = 1 , P = 2 , Q = 3 , R = 4 , S =5 , T = 6, U = 7 , V = 8 , W = 9 X = 10 , Y = 11, Z = 12, A = 13,B= 14, C =15,D= 16, E = 17, F= 18,G =19,H =20 , I = 21 , J = 22, K = 23 , L = 24 ,M = 25 , N = 26

NOW ADDING THE VALUES OF ALPHABET

OPEN = 1 + 2 + 17 + 26

SIMILARLY

PAINTER = 2 + 13 + 21 + 26 +  6 + 17 + 4  = 89

HENCE 89 IS CORRECT ANSWER