$\tan ^{-1} \frac{1}{\sqrt{3}}-\sin ^{-1} \frac{1}{2}$ is equal to:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 0
$\tan ^{-1} \frac{1}{\sqrt{3}}-\sin ^{-1} \frac{1}{2}=\frac{\pi}{6}-\frac{\pi}{6}=0$
$\tan ^{-1} \frac{1}{\sqrt{3}}-\sin ^{-1} \frac{1}{2}$ is equal to:
Correct answer: option 2
The correct answer is Option (2) → 0
$\tan ^{-1} \frac{1}{\sqrt{3}}-\sin ^{-1} \frac{1}{2}=\frac{\pi}{6}-\frac{\pi}{6}=0$