Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Inverse Trigonometric Functions

Question:

$\tan ^{-1} \frac{1}{\sqrt{3}}-\sin ^{-1} \frac{1}{2}$ is equal to:

Options:

$\frac{\pi}{4}$

0

$\frac{\pi}{3}$

$\frac{\pi}{2}$

Correct Answer:

0

Explanation:

The correct answer is Option (2) → 0