CUET Preparation Today
$\tan ^{-1} \frac{1}{\sqrt{3}}-\sin ^{-1} \frac{1}{2}$ is equal to: |
$\frac{\pi}{4}$ 0 $\frac{\pi}{3}$ $\frac{\pi}{2}$ |
0 |
The correct answer is Option (2) → 0 $\tan ^{-1} \frac{1}{\sqrt{3}}-\sin ^{-1} \frac{1}{2}=\frac{\pi}{6}-\frac{\pi}{6}=0$ |
