In a ΔABC, DE is parallel to BC, AD = 3 cm, AE = 4 cm and AC = 10 cm, then the value of BD in centimetres, is :
Answer & explanation
Correct answer: option 3
We know that,
If three angles of two triangles are equal then corresponding sides of similar triangles are proportional
We have,
In Δ ABC, AE = 4 cm
AD = 3 cm
AC = 10 cm
\(\frac{ AD }{ AB }\) = \(\frac{ AE }{ AC }\)
= \(\frac{ 3 }{ AB }\) = \(\frac{ 4 }{ 10 }\)
= AB = 7.5 cm
As, AB = AD + BD
= 7.5 = 3 + BD
= BD = 4.5 cm