CUET Preparation Today
The potential energy of an electron in the first excited state of hydrogen atom is -6.8 eV. The kinetic energy of the electron in it ground state will be: |
6.8 eV 13.6 eV -13.6 eV +27.6 eV |
13.6 eV |
The correct answer is Option (2) → 13.6 eV The energy of Bohr hydrogen atom model is - $E=\frac{13.6}{n^2}eV$ where, $n=1$ (for ground state) $E=13.6eV$ |
