The potential energy of an electron in the first excited state of hydrogen atom is -6.8 eV. The kinetic energy of the electron in it ground state will be:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 13.6 eV
The energy of Bohr hydrogen atom model is -
$E=\frac{13.6}{n^2}eV$
where,
$n=1$ (for ground state)
$E=13.6eV$