Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Numerical Ability

Topic

Percentages

Question:

The population of a town increases by 5% every year. If the present population of the town is 282240, then what was the population of the town 2 years ago?

Options:

266000

256000

228000

225000

Correct Answer:

256000

Explanation:

5% = \(\frac{1}{20}\) 

Let population 2 years ago = P

According to question,

P × \(\frac{21}{20}\) × \(\frac{21}{20}\) = 282240

P = 282240 × \(\frac{20}{21}\) × \(\frac{20}{21}\)

= 256000