If A and B are two non-singular matrices of order n, then which of the following statement/statements is/are not correct? (A) AB is non-singular. Choose the correct answer from the options given below: |
(A) and (C) only (A) only (B) and (D) only (B), (C) and (D) only |
(B), (C) and (D) only |
The correct answer is Option (4) → (B), (C) and (D) only Given: A and B are non-singular (invertible) n×n matrices. (A) AB is non-singular . If $A$ and $B$ are non-singular, then $|A| \neq 0$ and $|B| \neq 0$. The determinant of their product is $|AB| = |A| \cdot |B|$. Since neither determinant is zero, $|AB| \neq 0$. Therefore, $AB$ is non-singular. This statement is correct. (B) AB is singular . As established above, $AB$ is non-singular. Therefore, stating that $AB$ is singular is incorrect. (C) $(AB)^{-1} = A^{-1} B^{-1}$: The property for the inverse of a product is $(AB)^{-1} = B^{-1}A^{-1}$ (the reversal law). The expression $A^{-1}B^{-1}$ is generally not equal to $(AB)^{-1}$ unless the matrices commute ($AB = BA$). Therefore, this statement is incorrect. (D) $(AB)^{-1}$ does not exist . Since $AB$ is non-singular, its inverse must exist. Therefore, stating that it does not exist is incorrect. |