A mixture of water and milk contains 80% milk. In 50 litres of such a mixture, how many litres of water is required to increase the percentage of water to 25%?
Answer & explanation
Correct answer: option 1
Quantity of milk in the mixture = 50 x \(\frac{80}{100}\) = 40
Let the quantity of water to be added be x,
Then the quantity of milk reduces to 75%
\(\frac{10 + x}{40}\) = \(\frac{25}{75}\)
3 x (10 + x) = 40
3x = 10
x = 3.33