Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Wave Optics

Question:

Light is incident normally on a diffraction grating through which the first order diffraction is seen at 32°. The second order diffraction will be seen at

Options:

48°

64°

80°

there is no second order diffraction in this case.

Correct Answer:

there is no second order diffraction in this case.

Explanation:

For a grating $(e + d) \sin θ_n = nλ$

where (e + d) = grating element

$\sin θ_n = \frac{nλ}{(e + d)}$

for n = 1, $\sin θ_1 =\frac{λ}{(e + d)}=\sin 32°$

This is more than 0.5. Now sin θ2 will be more than 2 × 0.5, which is not possible.