Practicing Success
If the sum and product of the mean and variance of a binomial distribution are 18 and 72 respectively, then the probability of obtaining atmost one success is |
$25\left(\frac{1}{2}\right)^{24}$ $\left(\frac{1}{2}\right)^{24}$ $24\left(\frac{1}{2}\right)^{24}$ $24\left(\frac{1}{2}\right)^{23}$ |
$25\left(\frac{1}{2}\right)^{24}$ |