A boat takes one fourth time in moving a certain distance in downstream than in upstream. The speed of the boat in still water is how much percentage more than the speed of current?
Answer & explanation
Correct answer: option 2
If distance is constant, then ratio of speed = \(\frac{1}{ratio\;of\;time}\)
Downstream : Upstream
Time 1 : 4
Speed 4 : 1
Boat : Current
Speed \(\frac{4+1}{2}\) : \(\frac{4-1}{2}\)
5 : 3
Difference of speed = 2R
Speed of boat is = \(\frac{2}{3}\) × 100 = 66.66% more than the current.