Practicing Success
Practicing Success
CUET Preparation Today
A cell of e.m.f. E and internal resistance r is connected in series with an external resistance nr then the ratio of the terminal potential difference to E.M.F. is |
1/n $\frac{1}{n+1}$ $\frac{n}{n+1}$ $\frac{n+1}{n}$ |
$\frac{n}{n+1}$ |
$I = \frac{E}{nr+r} $ $ \text{Terminal potential } V = E -ir = E - \frac{E}{n+1} = \frac{nE}{n+1}$ |
