(A). The angles of depression of two ships from the top of a lighthouse are 60° and 45° towards the east. If the ships are 300 meter apart, the height of the lighthouse is $150(3+\sqrt{3})$ (B). If the surface area of a cube is $726 m^2$, then its volume shall be $1331 m^3$ (C) If the ratio of diameters of two spheres is 3 : 5, then the ratio of their surface area shall be 9 : 25 Determine as to which of the statements given above are correct. |
(A) & (B) Only (A), (B) & (C) (B) & (C) Only (A) & (C) Only |
(A), (B) & (C) |
The correct answer is Option (2) → (A), (B) & (C) Let us check each statement one by one. Statement (A) Let the height of the lighthouse = h
Distance between ships = $d_2 - d_1 = h - \frac{h}{\sqrt{3}} = h\left(1 - \frac{1}{\sqrt{3}}\right) = 300$ Solving, $h = \frac{300\sqrt{3}}{\sqrt{3}-1} = 150(3+\sqrt{3})$ Statement (A) is correct Statement (B) Surface area of cube = $6a^2 = 726$ $a^2 = 121 \Rightarrow a = 11$ Volume = $a^3 = 11^3 = 1331\ \text{m}^3$ Statement (B) is correct Statement (C) Surface area of a sphere ∝ $\text{(diameter)}^2$ Given ratio of diameters = 3 : 5 Surface area ratio $=\text{Surface area ratio} = 3^2 : 5^2 = 9 : 25$ Statement (C) is correct Correct Answer: (A), (B) & (C) |