Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

The work done by the field of a nucleus in a complete circular orbit of the electron is

Options:

$\frac{k (Ze) e}{r}$

$\frac{k (Ze) e}{r^2}$

$-\frac{k (Ze) e}{r^2}$

Zero

Correct Answer:

Zero

Explanation:

The correct answer is Option (4) - Zero

The nucleus exerts an electrostatic force on the orbiting electron. This force acts as the centripetal force and always point towards the centre of circular orbit -

$W=\vec F.\vec d=Fd\cos θ$

for a circular orbit, the force is always perpendicular to the instantaneous displacement of electron. 

$θ=90°$